Question 364152
Factor:
{{{3x^2+8x+4}}}
The first term has the factors: {{{highlight((3x)(x))}}}
The last term has the factors: {{{(1)(4)}}} or {{{highlight_green((2)(2))}}}
Since the middle term is: {{{8x}}} we can get this by {{{(3x)(2)+(x)(2)}}}, so...
{{{3x^2+8x+4 = (3x+2)(x+2)}}}