Question 364109
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Hi, 
A =(x + 5y)in( x^2 - 5xy -4y^2)in = x( x^2 - 5xy -4y^2) + 5y( x^2 - 5xy -4y^2)
Yes! simplifying results in:
x^3 - 20y^3 - 29xy^2
Area will be in in^2
{{{A = x^3in^2 - 29xy^2in^2 - 20y^3in^2}}}