Question 363981
Rectangle 1: (2x+3)(7x-5)=14x^2+11x-15
Rectangle 2: (3x-9)(8x-2)=24x^2-78x+18
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14x^2+11x-15=0
x=-1.5, x=.714... Between x=-1.5 and x=.714 y is negative.
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24x^2-78x+18=0
x=.25, x=3 Between x=.25 and x=3 y is negative.
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24x^2-78x+18-(14x^2+11x-15)=10x^2-89x+33
10x^2-89x+33=0
x=.3877..., x=8.512... 
For {{{.25<x<.714}}} both rectangles have a negative area.
For {{{.714<x<8.512}}} Rectangle 1 has a larger area than rectangle 2
For {{{0<x<.25}}} and {{{8.512<x<infinity}}} rectangle 2 has a larger area than rectangle 1.
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Ed