Question 363944
Reduce each answer to lowest terms.
(1/2-3/2x+1/x^2 )/(1/2-1/(2x^2 ))
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= [(x^2 - 3x + 2)/x^2]/[(x^2-1)/2x^2]
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= [(x^2 - 3x + 2)/x^2]*[(2x^2)/(x^2-1)]
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Factor and Cancel to get:
= [(x-2)/1] * [2/(x+1)]
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= [2(x-2)/(x+1)]
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Cheers,
Stan H.
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