Question 363803
{{{8/(a^2+a-6) = 6/(a^2-9)}}},
{{{8/((a+3)(a-2)) = 6/((a+3)(a-3))}}}.  Under assumption that a is not equal to -3, then 
{{{8/(a-2) = 6/(a-3)}}},
{{{4/(a-2) = 3/(a-3)}}},
{{{4a-12 = 3a-6}}}, after cross-multiplication.
a = 6.