Question 40537
{{{y = x^2 - 4x + 4}}}
{{{0 = x^2 - 4x + 4}}}
{{{0 = x^2 - 2x - 2x + 4}}}
{{{0 = (x^2 - 2x) + (-2x + 4)}}}
{{{0 = x(x - 2) - 2(x - 2)}}}
{{{0 = (x - 2)(x - 2)}}}
The x-intercept is at {{{2}}}.
*[invoke quadratic "x", 1, -4, 4]