Question 363381
I have worked this problem and I have it until I get to the last part of how I come up with the answer. 
z(5.8) = (5.8 -5.55)/0.65 = 0.385
P(x < 5.8) = P(z < 0.385) = 0.6499
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The diameter of apples in a certain orchard are normally distributed with a mean of 5.5 inches and a standard deviation of 0.65 inches. Show all work. 
What percentage of the apple in this orchard have diameters less than 5.8 inches?
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z(5.8) = (5.8 -5.55)/0.65 = 0.385
P(x < 5.8) = P(z < 0.385) = 0.6499
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What percentage of the apples in this orchard are larger than 6.3 inches?
z(6.3) = (6.3-5.55)0.65 = 1.1538
P(x> 6.3) = P(z > 1.1538) = 0.1243
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Cheers,
Stan H.
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