Question 363624
Use the quadratic formula,
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}} 
{{{x = (2 +- sqrt( (-2)^2-4*5*1 ))/(2*5) }}}
 {{{x = (2 +- sqrt( 4-20 ))/(10) }}}
{{{x = (2 +- sqrt( -16 ))/(10) }}}
{{{x = (2 +- 4i)/(10) }}}
{{{highlight(x = (1 +- 2i)/5)}}}