Question 363613
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Hi, 
*Note: exploring possible roots as being factors of the constant 3.
(1,3,-1,-3) found that -3 worked.
-27 + 27 + 3 - 3

          x^2  -   1
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x + 3 | x^3 +  3x^2 -  x - 3
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factoring would be 
F(x) = (x+3)(x-1)(x+1)

F(x) = 0 at x= -3, or x = -1 or x = 1