Question 363595
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Hi, 
ln(x(y^7)) 
writing the expression in terms of the logarithms of x and y: 
*[tex \large\ \ log_b(xy) = log_bx + log_by ]
ln(x(y^7)) = lnx + lny^7

2 ln(x) + 1/2 ln(y)
writing the expression as the logarithm of one quantity
*[tex \large\ \ alog_bx = log_b(x)^a ]
2 ln(x) + 1/2 ln(y) = ln(x^2) + ln(y^1/2)
*[tex \large\ \ log_bx + log_by = log_b(xy) ]
{{{ln(x^2) + ln(y^(1/2)) = ln(x^2*y^(1/2))}}}