Question 363229
Simplify
{{{4/((x^2-5x+4))}}} - {{{5/((x^2-1))}}}
we can factor both denominators
{{{4/((x-1)(x-4))}}} - {{{5/((x+1)(x-1))}}}
The common denominator will be (x-4)(x+1)(x-1), so we have
{{{(4(x+1) - 5(x-4))/((x-4)(x+1)(x-1))}}} = {{{((4x + 4 - 5x + 20))/((x-4)(x+1)(x-1))}}} = {{{((-x + 24))/((x-4)(x+1)(x-1))}}}; about all we can do with it