Question 363495
Complete the square.
{{{y=3x^2-6x+1}}}
{{{y=3(x^2-2x)+1}}}
{{{y=3(x^2-2x+1)+1-3}}}
{{{y=3(x-1)^2-2}}}
The vertex is ({{{1}}},{{{-2}}}).
The vertex lies on the axis of symmetry {{{x=1}}}.
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{{{drawing(300,300,-6,6,-6,6,grid(1),circle(1,-2,0.2),blue(line(1,10,1,-10)),graph(300,300,-6,6,-6,6,3x^2-6x+1))}}}