Question 363475
(E) I, II, and III.
We could have the following arrangement for the numbers:
2,3,3,6,x,y,20, in ascending order.  The mean is formed as follows:
{{{(2+3+3+6+x+y+20)/7  = (34+x+y)/7}}}.
If the average is 7, then x+y = 15, which is very much possible for two numbers x and y between 6 and 20.(Take  7 and 8, e.g.) If the average is 8.5, then x+y = 25.5, which again is possible for two numbers between 6 and 20 (take 10 and 15.5, e.g.)  If the average is 10, then x+y = 36, which again is possible for two numbers between 6 and 20 (take 17 and 19, e.g.)