Question 363426
I'm assuming the general form of the equation
is {{{y = mx + b}}}
Substituting:
{{{-4/5 = (-4/5)*x + 0}}}
solve for {{{x}}}
Multiply both sides by {{{-5/4}}}
{{{1 = x}}}
This says that {{{x=1}}} no matter what {{{y}}} is, so
the graph is a vertical line passing through (1,0), (1,1),
(1,2), (1,3),(1, -1), (1,-2),(1,-3) etc. on to infinity in both 
+y and -y directions