Question 363403
log(base 2)[(y^2*(cube root of (x^2*y))]/z^4 
= log(base 2)(y^2) + log(base 2)(cube root of (x^2*y))-log (base 2)(z^4) (USING LAWS OF LOGARITHMS)
2*LOG(BASE 2)y +(1/3)log (base 2)(x^2y)-4 log (base 2)z
=2*LOG(BASE 2)y +(1/3)[log (base 2 )(x^2)+log (base 2)y]-4 log (base 2)z
=2*LOG(base 2)y +(1/3)[ 2 log (base 2 )x +log (base 2)y]-4 log (base 2)z
=2q+(1/3)(2p +q)-4r
=(2/3)p + 2q +(1/3)q - 4r
 =(2/3) p + (7/3) q - 4r