<PRE><B>Question 363153</B>
i) An object is positioned at the origin of the xy axis, Two forces act upon it, the first has magnitude of 9N and acts in the direction of the y-axis, The second has magnitude 4N and acts in the direction of the negative x axis, Calculate the magnitude and direction of the resultant force R.
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d = sqrt(9^2+4^2) = sqrt(97)
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direction invtan(9/-4) = 180-66.038 = 113.96 degrees
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(ii) An object moves in the xy plane with a velocity of 15ms^-1 in a direction 36.87degrees above the positive x axis. Resolve this velocity into two components, one labeled X along the x-axis and the other labeled Y along the y-axis
x =  15*cos(36.87) = 12 
y =  15*sin(36.87) = 9 
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Cheers,
Stan H.
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