Question 363241
The 12-foot bed of a dump truck loaded with heavy stone must rise to an angle of 36° before the stone will spill out. Approximately how high must the front of the bed rise (x) to unload?
sin 36° ≈ 0.588.


Let a° represent the angle made by the bed of the truck when it is raised.
By definition        (adjacent side) times sin a° = opposite side
                                           

(12 feet) times sin 36°=  x feet      
	   
                           x = 12 sin 36°
                           x = 12(0.588)
                           x = 7.056 feet

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