Question 363233
Use the common denominator, {{{(x+4)(x-4)}}}
{{{1/(x-4)+1/(x+4)=(x+4)/((x-4)(x+4))+(x-4)/((x-4)(x+4))}}}
{{{1/(x-4)+1/(x+4)=(x+4+x-4)/((x-4)(x+4))}}}
{{{highlight(1/(x-4)+1/(x+4)=(2x)/((x-4)(x+4)))}}}