Question 363215
Provide answers in interval notation . 
s^2 - 2s - 35 < 0
----
Find the boundary value for "s":
---
s^2 - 2s - 35 = 0
(x-7)(x+5) = 0
x = -5 or x = 7
----------------------
Plot x=-5 and x=7 on a number line.
---
Check a value from each of the resulting intervals
in the INEQUALITY:
(x-7)(x+5) < 0
---
Let x = -10 to get: -*- < 0 ; false
Let x = 0 to get: -*+ < 0 ; true, so solutions in (-5,7)
Let x = 10 to get: +*+ < 0 ; false
--------------
Solution interval: (-5,7)
================
Cheers,
Stan H.