<PRE><B>Question 363157</B>
Please help me factor this polynomial:8x^3-12x^2+6x-1 . I am trying to figure out how to solve it using the factor theorem. My answer key uses 2 as the factor of the constant term. 
And then the synthetic division looks like this: 1-6 12-8
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I graphed the cubic and found a zero at x = 1/2.
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(1/2)....8....-12....6....-1
..........8......-8....2...| 0

Factors: (2x-1)(8x^2 - 8x + 2)
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You can factor further.
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Cheers,
Stan H.</PRE>