Question 363123
Use the identities {{{y*ln(x)=ln(x^y)}}}, {{{ln(A)-ln(B)=ln(A/B)}}}, and {{{x^(1/2)^""=sqrt(x)}}} to get



{{{(1/2)ln(x)-ln(3)=ln(x^(1/2)^"")-ln(3)=ln((x^(1/2)^"")/3)=ln((sqrt(x))/3)}}}




So {{{(1/2)ln(x)-ln(3)=ln((sqrt(x))/3)}}}