Question 363125


{{{2x-4y=16}}} Start with the given equation.



{{{-4y=16-2x}}} Subtract {{{2x}}} from both sides.



{{{-4y=-2x+16}}} Rearrange the terms.



{{{y=(-2x+16)/(-4)}}} Divide both sides by {{{-4}}} to isolate y.



{{{y=((-2)/(-4))x+(16)/(-4)}}} Break up the fraction.



{{{y=(1/2)x-4}}} Reduce.



So the equation {{{y=(1/2)x-4}}} is now in slope intercept form {{{y=mx+b}}} where the slope is {{{m=1/2}}} and the y-intercept is {{{b=-4}}} note: the y-intercept is the point *[Tex \LARGE \left(0,-4\right)]