Question 362880
Let {{{S=sin(x)}}}, {{{C=cos(x)}}}, {{{T=tan(x)}}},
.
.

{{{1/T^2-C^2=C^2/T^2}}}
{{{1-T^2C^2=C^2}}}
{{{1-(S^2/C^2)C^2=C^2}}}
{{{1-S^2=C^2}}}
{{{highlight(S^2+C^2=1)}}}
True.