Question 362969
{{{a^3 - 54=0}}} 
{{{a^3= 54}}}
{{{highlight(a=root(3,54))}}} or approximately
{{{a=3.78}}}

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Please explain this "2*3rd".
Is that the cube root of {{{(x+4)}}}?
If so, then
{{{2*root(3,(x+4))=10}}}
{{{root(3,(x+4))=5}}}
{{{x+4=125}}}
{{{highlight(x=121)}}}
If that's not what you meant, please re-post.