Question 363008
A man is 24 years older than his son. In two years, his age will be twice the age of his son. what is the present age of his son? 
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son's age = xyears
father's age = x=24 years
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after 2 years
son = x+2
father = x+24+2= x+26
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x+26=2(x+2)
x+26=2x+4
2x-x=26-4
x=22 years son's age
father's age = 24+22=46 years
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m.ananth@hotmail.ca