Question 362980
(7x^2-12)^(1/4)=x 
Raise it by 4 power
(7x^2-12)^(1/4 *4)= x^4
7x^2-12=x^4
x^4-7x^2+12=0
x^4-4x^2-3x^2+12=0
x^2(x^2-4)-3(x^2-4)=0
(x^2-4)(x^2-3)=0
(x+2)(x-2)(x^2-3)=0
x= +/- 2
x=+/- sqrt(3)
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