Question 40334
Solve quadratic equation by quadratic formula.
x2 + 3x + 1 = 0
When we use the quadratic formula: {{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}
we simply need to "plug-in" the corresponding values.
REMEMBER: The -b in this formula is the OPPOSITE of the value of b. 
Now we simply insert the coefficients of our equation such that a = 1, b = 3, c = 1
{{{y = (-3 +- sqrt( 3^2-4*1*1 ))/(2*1) }}}
and solve...
{{{y = (-3 +- sqrt( 9 - 4 ))/(2) }}}
and...
{{{y = (-3 +- sqrt( 5 ))/(2) }}}
This is pretty much the most it can be simplified.
So our solution set would be...
{{{y = (-3 + sqrt( 5 ))/(2) }}} , {{{y = (-3 - sqrt( 5 ))/(2) }}}
I hope this helps.
Good Luck!