Question 362520
Remember that {{{log(b,(b^x))=x}}} and that {{{b^(log(b,x))=x}}}


a) Let b=6 and x=9 to get {{{log(6,(6^9))=9}}}


b) Let b=e and replace x with -3x to get {{{ln(e^(-3x))=-3x}}}


Note: ln is the natural log (ie the log with base 'e').