Question 362507
If you add their rates and multiply by elapsed time,
that is their distance apart
Let speed of 2nd cyclist = {{{r}}} mi/hr
Then speed of 1st cyclist = {{{r + 5}}} mi/hr
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{{{70 = (r + r + 5)*2}}}
{{{2r + 5 = 35}}}
{{{2r = 30}}}
{{{r = 15}}}
and
{{{r + 5 = 20}}}
The 1st cyclist's speed is 20 mi/hr
The 2nd cyclist's speed is 15 mi/hr