Question 362446
The answer is -1/16..
Observe..

{{{ 7^(-x) = 1/4 }}} and you want to solve {{{ 49^x }}} where we can write it as {{{ 7^2^x }}} and also as{{{ 7^x^2 }}} and also as{{{ 7^(-x)^(-2) }}}

If you give a name to {{{ 7^(-x) }}} as "a" 

We'll have {{{ a^(-2) }}}

If {{{ a = 1/4 }}} >> so {{{ (1/4)^(-2) }}} equals to {{{ -1/16 }}} 

RF.