Question 362323
Since it's a right triangle, use the Pythagorean theorem.
{{{A^2+B^2=H^2}}}
{{{23^2+b^2=26^2}}}
{{{529+b^2=676}}}
{{{b^2=147}}}
{{{b=sqrt(147)}}}
{{{highlight(b=7sqrt(3))}}}