Question 362442
A man wanted to get into his work building, but he had forgotten his Code. However, he did remember five clues. These are what those clues were:
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Let A = 1st number.
Let B = 2nd number.
Let C = 3rd number.
Let D = 4th number.
Let E = 5th number.


The fifth number plus the third number equals fourteen.

E + C = 14

The fourth number is one more than the second number.

D = B + 1

The first number is one less than twice the second number.

A = 2B - 1

The second number plus the third number equals ten.

B + C = 10

The sum of all five numbers is 30.

A + B + C + D + E = 30

What were the five numbers and in what order?

(1)  E + C = 14
(2)  D = B + 1
(3)  A = 2B - 1
(4)  B + C = 10
(5)  A + B + C + D + E = 30

Write the equations up so that corresponding 
terms line up vertically

(1)            C     + E = 14
(2)       -B     + D     =  1
(3)  A  - 2B             = -1
(4)        B + C         = 10
(5)  A  +  B + C + D + E = 30

Can you solve that system?  If not ask me how to.

A=7, B=4, C=6, D=5, E=8

Edwin</pre>