Question 362352
{{{6/(x-3) + 8/(3-x)}}}

Write the second denominator in descending order:

{{{6/(x-3) + 8/(-x+3)}}}

Factor -1 out of the second denominator:

{{{6/(x-3) + 8/(-1(x-3))}}}

The -1 on the bottom of the second fraction makes
the term negative so we just us a minus sign:

{{{6/(x-3) - 8/(x-3)}}}

Now the two fractions have the same denominator:

{{{(6-8)/(x-3)}}}

{{{-2/(x-3)}}}

Edwin</pre>