Question 362376
{{{drawing(300,300,-2,7,-2,20,
blue(line(0.5,16,1.5,16)),
blue(line(1.5,17,2.5,17)),
blue(line(2.5,17,3.5,17)),
blue(line(3.5,17,4.5,17)),
blue(line(4.5,17,5.5,17)),
blue(line(5.5,16,6.5,16)),
blue(line(1.5,0,1.5,17)),
blue(line(2.5,0,2.5,17)),
blue(line(3.5,0,3.5,17)),
blue(line(4.5,0,4.5,17)),
blue(line(5.5,0,5.5,16)),
blue(line(0.5,0,0.5,16)),
blue(line(6.5,0,6.5,16)),
blue(line(5.5,16,5.5,17)),
graph(300,300,-2,7,-2,20,0))}}}
You would expect equal probabilities for each value. 
However since 100 is not exactly divisible by 6, you will have 4 values at 17 and 2 values at 16. Assigning the values is arbitrary.