Question 362375
You mean what is the solution.
Substitute eq. 2 into eq. 1,
{{{2x-5(3x+4)=10}}}
{{{2x-15x-20=10}}}
{{{-13x=30}}}
{{{highlight(x=-30/13)}}}
Now use eq. 2 to solve for {{{y}}},
{{{y=3(-30/13)+4}}}
{{{y=-90/13+52/13}}}
{{{highlight(y=-38/13)}}}