Question 362368
let the number be x& y
xy=15
x=15/y
..
x=4y+7

plug value of x
15/y=4y+7
15=y(4y+7)
15=4y^2+7y
4y^2+7y-15=0
4y^2+12y-5y-15=0
4y(y+3)-5(y+3)=0
(y+3)(4y-5)
so y =-3
...
plug value of y in the equation
x= -5
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