Question 362218
The point is that you have to get out of square root and fraction in both sides..

If you take 6th degree of square of both sides you'll solve this..Observe >>

{{{ ((x-1)^ (1/3))^6 = (sqrt( x ))^6 }}}

{{{ (x-1)^2 = x^3 }}}  as (1/3)*6 = 2(left side) and 6/2 = 3 (right side)

After then >>

 {{{ x^2 - 2x + 1 = x^3 }}} so that {{{ x^3 - x^2 + 2x - 1 = 0 }}}

You can not solve this immediately as it's not a regular cubic equation. You have to find roots.Check from any search engine to find roots of cubic equation.

RF.