Question 361926
F=(9/5)*C (degrees)+32
plug the value of C in the equation
F=(9/5)*32+32
F=57.6+32
F=89.6 deg 
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ALso what if the temp is -40degreesF, what woulld it be in celsius
-40=(9/5)*C +32
add -32
-40-32= 9/5*c
-72=9/5*c
5*-72/9 =C
c= -40 deg
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