Question 361628
{{{16^x * 4^(x-2) = 1/64}}}
Take the log to the base 4 of both sides
{{{log(4,16^x) + log(4,4^(x-2)) = log(4,1/64)}}}
{{{x*2 + (x-2)*1 = -3}}}
{{{2x + x - 2 = -3}}}
{{{3x = -1}}}
{{{x = -1/3}}}