Question 361448
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 5\sin(x)\ =\ 2]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \sin(x)\ =\ \frac{2}{5}]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \sin(\varphi)\ >\ 0] in QI and QII, hence:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x\ =\ \sin^{-1}\left(\frac{2}{5}\right)\ \approx\ 23.58^\circ]


Or


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x\ =\ 180\ -\ \sin^{-1}\left(\frac{2}{5}\right)\ \approx\ 156.42^\circ]




John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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