Question 361342
a)Find vertex of quadratic 
g(x)=(x-2)^2-1
Vertex: (2,-1)
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b) determine the # of x intercepts
Since the vertex is below the x-axis and since
the parabola opens upward, it intersects the
axis at two points.
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C)graph this quadratic function by 2 points on the parabolax---
Solve (x-2)^2-1 = 0
x-2 = 1 or x-2 = -1
x = 3 or x = 1
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{{{graph(400,300,-10,10,-10,10,(x-2)^2-1)}}}
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Cheers,
Stan H.