Question 361286
{{{2x - 11sqrt(x) - 40 = 0}}}
You can sub y for sqrt(x)
{{{2y^2 - 11y - 40 = 0}}}
(2y+5)*(y-8) = 0
y = 8
--> x = 64
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2y+5 = 0
y = -5/2
-->x = 25/4 This fits if you use the neg root.