Question 40336
Solve:
{{{(2x+2)^2 = 64}}} Take the square root of both sides.
{{{2x+2 = +8}}} or {{{2x+2 = -8}}}

{{{2x+2 = 8}}} Subtract 2 from both sides.
{{{2x = 6}}} Divide both sides by 2.
{{{x = 3}}}

{{{2x+2 = -8}}} Subtract 2 from both sides.
{{{2x = -10}}} Divide both sides by 2.
{{{x = -5}}}

The roots are:
x = 3
x = -5