Question 40337
Solve by factoring:
{{{2y^2-3y-2 = 0}}} Factor.
{{{(2y+1)(y-2) = 0}}} Apply the zero products principle.
{{{2y+1 = 0}}} and/or {{{y-2 = 0}}}
If {{{2y+1 = 0}}} then {{{2y = -1}}} and {{{y = -1/2}}}
If {{{y-2 = 0}}} then {{{y = 2}}}
The roots are:
{{{y = -1/2}}}
{{{y = 2}}}