Question 361121
{{{3X^2+3X=5}}}

 {{{3X^2+3X-5=0}}}
 {{{3X^2-12X+15X-5=0 }}}        [-12X+15X=3X]
 {{{3X(X-4)-5(3X-1)=0}}}
 {{{(3X-5)(X-4)(3X-1)=0}}}
 from the above solution we can understand that,either
 3X-5=0
 3X=5
 {{{X=5/3}}}...(1) or
 
 X-4=o
 {{{X=4}}}.....(2) or

 3X-1=0
 3X=1
 {{{X=1/3}}}....(3)
  hence the values (or cubes) are 5/3, 4, 1/3