<PRE><B>Question 360786</B>
a spinner has regions numbered 1 through 21. what is the probability that the spinner will stop on an even number or a mulitiple of 3? reduce fraction if necessary.
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Even: 2,4,6,8,10,12,14,16,18,20: 10 ways
Even and multiple of 3: 6,12,18: 3 ways
Multiples of 3: 3,6,9,12,15,18,21: 7 ways
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Possible results: 21
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P(even or multiple of 3) = P(even) + P(multiple) - P(even and multiple of 3)
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= (10 + 7 - 3)/21 = 14/21 = 2/3
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Cheers,
Stan H.
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