Question 360729
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Hi,
*Note: format of a line for using the quadratic equaton 
ax^2 + bx + c = 0
x^2 + 15x + 56=0 (given in the necessary format, no preliminary steps need to be taken)
a = 1 b = 15 and c = 56
Using the quadratic formula to solve the equation.
 {{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}
{{{x = (-15 +- sqrt( 15^2-4*1*56 ))/(2) }}}
{{{x = (-15 +- sqrt( 225-224 ))/(2) }}}
{{{x = (-15 +- sqrt( 1 ))/(2) }}}
{{{x = (-15 +- 1)/(2) }}}
x = -16/2 = -8
x = -14/2 = -7