Question 360682
What is the vertex of function {{{y=-x^2-5x-2}}}?
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{{{y=-(x^2+5x)-2}}}     factor a -1 from the first two terms

{{{y=-(x^2+5x+25/4-25/4)-2}}}  add and subtract 25/4 to complete the square
{{{y=-(x+5/2)^2+25/4-2}}}
{{{y= -(x+5/2)^2+25/4-8/4=-(x+5/2)^2+17/4}}}
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vertex  x=-5/2, y=17/4