Question 360646
15eX-12=17
I added 12 to 17 to remove it and got 15eX=29 but im not sure if i should divde or what i am supposed to do next?
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If x is the exponent, and not x-12:
{{{15e^x - 12 = 17}}}
{{{15e^x = 29}}}
{{{e^x = 29/15}}}
{{{ln(e^x) = ln(29/15)}}}
x = ln(29/15)
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x =~ 0.6592