Question 360642
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Hi,
4x^2 + 3x = 5
solve using the quadratic formula
4x^2 + 3x - 5 = 0
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}
{{{x = (-3 +- sqrt( 3^2-4*4*(-5) ))/(8) }}}
{{{x = (-3 +- sqrt( 9 + 80 ))/(8) }}}
{{{x = (-3 +- sqrt(89))/(8) }}}

3x^2 = 3-5x 
solve using the quadratic formula
3x^2+ 5x -3 = 0 
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}
{{{x = (-5 +- sqrt( 5^2-4*3*(-3) ))/(6) }}}
{{{x = (-5 +- sqrt(25+36 ))/(6) }}}
{{{x = (-5 +- sqrt(61))/(6) }}}
Will leave it up to you to complete steps necessary with your calculator to have the solutions
in the format required in your class.